(2x^2-25)=(3x^2+60)

Solution for (2x^2-25)=(3x^2+60) equation:

(2x^2-25)=(3x^2+60)

We move all terms to the left:

(2x^2-25)-((3x^2+60))=0

We get rid of parentheses

2x^2-((3x^2+60))-25=0


We calculate terms in parentheses: -((3x^2+60)), so:

(3x^2+60)

We get rid of parentheses

3x^2+60

Back to the equation:

-(3x^2+60)


We get rid of parentheses

2x^2-3x^2-60-25=0

We add all the numbers together, and all the variables

-1x^2-85=0

a = -1; b = 0; c = -85;
Δ = b2-4ac
Δ = 02-4·(-1)·(-85)
Δ = -340
Delta is less than zero, so there is no solution for the equation